Average Error: 0 → 0
Time: 574.0ms
Precision: 64
\[\left(x \cdot 16\right) \cdot x\]
\[\left(x \cdot 16\right) \cdot x\]
\left(x \cdot 16\right) \cdot x
\left(x \cdot 16\right) \cdot x
double f(double x) {
        double r187303 = x;
        double r187304 = 16.0;
        double r187305 = r187303 * r187304;
        double r187306 = r187305 * r187303;
        return r187306;
}

double f(double x) {
        double r187307 = x;
        double r187308 = 16.0;
        double r187309 = r187307 * r187308;
        double r187310 = r187309 * r187307;
        return r187310;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0

    \[\left(x \cdot 16\right) \cdot x\]
  2. Final simplification0

    \[\leadsto \left(x \cdot 16\right) \cdot x\]

Reproduce

herbie shell --seed 2019325 +o rules:numerics
(FPCore (x)
  :name "Graphics.Rasterific.CubicBezier:isSufficientlyFlat from Rasterific-0.6.1"
  :precision binary64
  (* (* x 16) x))