Average Error: 0.0 → 0.0
Time: 8.6s
Precision: 64
\[e^{\left(x \cdot y\right) \cdot y}\]
\[e^{\left(x \cdot y\right) \cdot y}\]
e^{\left(x \cdot y\right) \cdot y}
e^{\left(x \cdot y\right) \cdot y}
double f(double x, double y) {
        double r200712 = x;
        double r200713 = y;
        double r200714 = r200712 * r200713;
        double r200715 = r200714 * r200713;
        double r200716 = exp(r200715);
        return r200716;
}

double f(double x, double y) {
        double r200717 = x;
        double r200718 = y;
        double r200719 = r200717 * r200718;
        double r200720 = r200719 * r200718;
        double r200721 = exp(r200720);
        return r200721;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[e^{\left(x \cdot y\right) \cdot y}\]
  2. Final simplification0.0

    \[\leadsto e^{\left(x \cdot y\right) \cdot y}\]

Reproduce

herbie shell --seed 2019323 +o rules:numerics
(FPCore (x y)
  :name "Data.Random.Distribution.Normal:normalF from random-fu-0.2.6.2"
  :precision binary64
  (exp (* (* x y) y)))