Average Error: 0.0 → 0.0
Time: 5.7s
Precision: 64
\[x \cdot \left(1 - x \cdot 0.5\right)\]
↓
\[x \cdot \left(1 - x \cdot 0.5\right)\]
x \cdot \left(1 - x \cdot 0.5\right)
↓
x \cdot \left(1 - x \cdot 0.5\right)
double f(double x) {
        double r29498 = x;
        double r29499 = 1.0;
        double r29500 = 0.5;
        double r29501 = r29498 * r29500;
        double r29502 = r29499 - r29501;
        double r29503 = r29498 * r29502;
        return r29503;
}
↓
double f(double x) {
        double r29504 = x;
        double r29505 = 1.0;
        double r29506 = 0.5;
        double r29507 = r29504 * r29506;
        double r29508 = r29505 - r29507;
        double r29509 = r29504 * r29508;
        return r29509;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[x \cdot \left(1 - x \cdot 0.5\right)\]

  2. Final simplification0.0

    \[\leadsto x \cdot \left(1 - x \cdot 0.5\right)\]

Reproduce

herbie shell --seed 2019323 +o rules:numerics
(FPCore (x)
  :name "Numeric.SpecFunctions:log1p from math-functions-0.1.5.2, B"
  :precision binary64
  (* x (- 1 (* x 0.5))))