Average Error: 0.0 → 0.0
Time: 7.4s
Precision: 64
\[x \cdot \left(1 - x \cdot 0.5\right)\]
↓
\[x \cdot \left(1 - x \cdot 0.5\right)\]
x \cdot \left(1 - x \cdot 0.5\right)
↓
x \cdot \left(1 - x \cdot 0.5\right)
double f(double x) {
        double r29536 = x;
        double r29537 = 1.0;
        double r29538 = 0.5;
        double r29539 = r29536 * r29538;
        double r29540 = r29537 - r29539;
        double r29541 = r29536 * r29540;
        return r29541;
}
↓
double f(double x) {
        double r29542 = x;
        double r29543 = 1.0;
        double r29544 = 0.5;
        double r29545 = r29542 * r29544;
        double r29546 = r29543 - r29545;
        double r29547 = r29542 * r29546;
        return r29547;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[x \cdot \left(1 - x \cdot 0.5\right)\]

  2. Final simplification0.0

    \[\leadsto x \cdot \left(1 - x \cdot 0.5\right)\]

Reproduce

herbie shell --seed 2019323 +o rules:numerics
(FPCore (x)
  :name "Numeric.SpecFunctions:log1p from math-functions-0.1.5.2, B"
  :precision binary64
  (* x (- 1 (* x 0.5))))