Average Error: 39.1 → 0.0
Time: 19.5s
Precision: 64
\[\left(x + 1\right) \cdot \left(x + 1\right) - 1\]
\[x \cdot x + x \cdot 2\]
\left(x + 1\right) \cdot \left(x + 1\right) - 1
x \cdot x + x \cdot 2
double f(double x) {
        double r11574 = x;
        double r11575 = 1.0;
        double r11576 = r11574 + r11575;
        double r11577 = r11576 * r11576;
        double r11578 = r11577 - r11575;
        return r11578;
}

double f(double x) {
        double r11579 = x;
        double r11580 = r11579 * r11579;
        double r11581 = 2.0;
        double r11582 = r11579 * r11581;
        double r11583 = r11580 + r11582;
        return r11583;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 39.1

    \[\left(x + 1\right) \cdot \left(x + 1\right) - 1\]
  2. Taylor expanded around 0 0.0

    \[\leadsto \color{blue}{{x}^{2} + 2 \cdot x}\]
  3. Simplified0.0

    \[\leadsto \color{blue}{x \cdot \left(x + 2\right)}\]
  4. Using strategy rm
  5. Applied distribute-lft-in0.0

    \[\leadsto \color{blue}{x \cdot x + x \cdot 2}\]
  6. Final simplification0.0

    \[\leadsto x \cdot x + x \cdot 2\]

Reproduce

herbie shell --seed 2019323 
(FPCore (x)
  :name "Expanding a square"
  :precision binary64
  (- (* (+ x 1) (+ x 1)) 1))