Average Error: 0.0 → 0.0
Time: 7.3s
Precision: 64
\[x \cdot e^{y \cdot y}\]
↓
\[x \cdot e^{y \cdot y}\]
x \cdot e^{y \cdot y}
↓
x \cdot e^{y \cdot y}
double f(double x, double y) {
        double r476215 = x;
        double r476216 = y;
        double r476217 = r476216 * r476216;
        double r476218 = exp(r476217);
        double r476219 = r476215 * r476218;
        return r476219;
}
↓
double f(double x, double y) {
        double r476220 = x;
        double r476221 = y;
        double r476222 = r476221 * r476221;
        double r476223 = exp(r476222);
        double r476224 = r476220 * r476223;
        return r476224;
}

Error

Bits error versus x

Bits error versus y

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Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.0
Target0.0
Herbie0.0
\[x \cdot {\left(e^{y}\right)}^{y}\]

Derivation

  1. Initial program 0.0

    \[x \cdot e^{y \cdot y}\]

  2. Final simplification0.0

    \[\leadsto x \cdot e^{y \cdot y}\]

Reproduce

herbie shell --seed 2019323 
(FPCore (x y)
  :name "Data.Number.Erf:$dmerfcx from erf-2.0.0.0"
  :precision binary64

  :herbie-target
  (* x (pow (exp y) y))

  (* x (exp (* y y))))