Average Error: 0.0 → 0.0
Time: 7.6s
Precision: 64
\[x \cdot \left(1 - x \cdot 0.5\right)\]
↓
\[x \cdot \left(1 - x \cdot 0.5\right)\]
x \cdot \left(1 - x \cdot 0.5\right)
↓
x \cdot \left(1 - x \cdot 0.5\right)
double f(double x) {
        double r51871 = x;
        double r51872 = 1.0;
        double r51873 = 0.5;
        double r51874 = r51871 * r51873;
        double r51875 = r51872 - r51874;
        double r51876 = r51871 * r51875;
        return r51876;
}
↓
double f(double x) {
        double r51877 = x;
        double r51878 = 1.0;
        double r51879 = 0.5;
        double r51880 = r51877 * r51879;
        double r51881 = r51878 - r51880;
        double r51882 = r51877 * r51881;
        return r51882;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[x \cdot \left(1 - x \cdot 0.5\right)\]

  2. Final simplification0.0

    \[\leadsto x \cdot \left(1 - x \cdot 0.5\right)\]

Reproduce

herbie shell --seed 2019323 
(FPCore (x)
  :name "Numeric.SpecFunctions:log1p from math-functions-0.1.5.2, B"
  :precision binary64
  (* x (- 1 (* x 0.5))))