Average Error: 0 → 0
Time: 511.0ms
Precision: 64
\[\left(x \cdot 16\right) \cdot x\]
\[\left(x \cdot 16\right) \cdot x\]
\left(x \cdot 16\right) \cdot x
\left(x \cdot 16\right) \cdot x
double f(double x) {
        double r131684 = x;
        double r131685 = 16.0;
        double r131686 = r131684 * r131685;
        double r131687 = r131686 * r131684;
        return r131687;
}

double f(double x) {
        double r131688 = x;
        double r131689 = 16.0;
        double r131690 = r131688 * r131689;
        double r131691 = r131690 * r131688;
        return r131691;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0

    \[\left(x \cdot 16\right) \cdot x\]
  2. Final simplification0

    \[\leadsto \left(x \cdot 16\right) \cdot x\]

Reproduce

herbie shell --seed 2019323 +o rules:numerics
(FPCore (x)
  :name "Graphics.Rasterific.CubicBezier:isSufficientlyFlat from Rasterific-0.6.1"
  :precision binary64
  (* (* x 16) x))