Average Error: 0.0 → 0.0
Time: 6.5s
Precision: 64
\[x \cdot \left(1 - x \cdot 0.5\right)\]
↓
\[x \cdot \left(1 - x \cdot 0.5\right)\]
x \cdot \left(1 - x \cdot 0.5\right)
↓
x \cdot \left(1 - x \cdot 0.5\right)
double f(double x) {
        double r52913 = x;
        double r52914 = 1.0;
        double r52915 = 0.5;
        double r52916 = r52913 * r52915;
        double r52917 = r52914 - r52916;
        double r52918 = r52913 * r52917;
        return r52918;
}
↓
double f(double x) {
        double r52919 = x;
        double r52920 = 1.0;
        double r52921 = 0.5;
        double r52922 = r52919 * r52921;
        double r52923 = r52920 - r52922;
        double r52924 = r52919 * r52923;
        return r52924;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[x \cdot \left(1 - x \cdot 0.5\right)\]

  2. Final simplification0.0

    \[\leadsto x \cdot \left(1 - x \cdot 0.5\right)\]

Reproduce

herbie shell --seed 2019323 
(FPCore (x)
  :name "Numeric.SpecFunctions:log1p from math-functions-0.1.5.2, B"
  :precision binary64
  (* x (- 1 (* x 0.5))))