Average Error: 0.0 → 0.0
Time: 7.5s
Precision: 64
\[e^{\left(x \cdot y\right) \cdot y}\]
\[e^{\left(x \cdot y\right) \cdot y}\]
e^{\left(x \cdot y\right) \cdot y}
e^{\left(x \cdot y\right) \cdot y}
double f(double x, double y) {
        double r116323 = x;
        double r116324 = y;
        double r116325 = r116323 * r116324;
        double r116326 = r116325 * r116324;
        double r116327 = exp(r116326);
        return r116327;
}

double f(double x, double y) {
        double r116328 = x;
        double r116329 = y;
        double r116330 = r116328 * r116329;
        double r116331 = r116330 * r116329;
        double r116332 = exp(r116331);
        return r116332;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[e^{\left(x \cdot y\right) \cdot y}\]
  2. Final simplification0.0

    \[\leadsto e^{\left(x \cdot y\right) \cdot y}\]

Reproduce

herbie shell --seed 2019322 +o rules:numerics
(FPCore (x y)
  :name "Data.Random.Distribution.Normal:normalF from random-fu-0.2.6.2"
  :precision binary64
  (exp (* (* x y) y)))