Average Error: 0.0 → 0.0
Time: 11.3s
Precision: 64
\[5 \le a \le 10 \land 0.0 \le b \le 0.001000000000000000020816681711721685132943\]
\[\left(a + b\right) \cdot \left(a + b\right)\]
\[b \cdot \left(2 \cdot a + b\right) + a \cdot a\]
\left(a + b\right) \cdot \left(a + b\right)
b \cdot \left(2 \cdot a + b\right) + a \cdot a
double f(double a, double b) {
        double r89274 = a;
        double r89275 = b;
        double r89276 = r89274 + r89275;
        double r89277 = r89276 * r89276;
        return r89277;
}

double f(double a, double b) {
        double r89278 = b;
        double r89279 = 2.0;
        double r89280 = a;
        double r89281 = r89279 * r89280;
        double r89282 = r89281 + r89278;
        double r89283 = r89278 * r89282;
        double r89284 = r89280 * r89280;
        double r89285 = r89283 + r89284;
        return r89285;
}

Error

Bits error versus a

Bits error versus b

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.0
Target0.0
Herbie0.0
\[\left(\left(b \cdot a + b \cdot b\right) + b \cdot a\right) + a \cdot a\]

Derivation

  1. Initial program 0.0

    \[\left(a + b\right) \cdot \left(a + b\right)\]
  2. Taylor expanded around 0 0.0

    \[\leadsto \color{blue}{{a}^{2} + \left(2 \cdot \left(a \cdot b\right) + {b}^{2}\right)}\]
  3. Simplified0.0

    \[\leadsto \color{blue}{b \cdot \left(2 \cdot a + b\right) + a \cdot a}\]
  4. Final simplification0.0

    \[\leadsto b \cdot \left(2 \cdot a + b\right) + a \cdot a\]

Reproduce

herbie shell --seed 2019322 
(FPCore (a b)
  :name "Expression 4, p15"
  :precision binary64
  :pre (and (<= 5 a 10) (<= 0.0 b 0.001))

  :herbie-target
  (+ (+ (+ (* b a) (* b b)) (* b a)) (* a a))

  (* (+ a b) (+ a b)))