Average Error: 0.0 → 0.0
Time: 4.8s
Precision: 64
\[x \cdot \left(1 - x \cdot 0.5\right)\]
↓
\[x \cdot \left(1 - x \cdot 0.5\right)\]
x \cdot \left(1 - x \cdot 0.5\right)
↓
x \cdot \left(1 - x \cdot 0.5\right)
double f(double x) {
        double r52525 = x;
        double r52526 = 1.0;
        double r52527 = 0.5;
        double r52528 = r52525 * r52527;
        double r52529 = r52526 - r52528;
        double r52530 = r52525 * r52529;
        return r52530;
}
↓
double f(double x) {
        double r52531 = x;
        double r52532 = 1.0;
        double r52533 = 0.5;
        double r52534 = r52531 * r52533;
        double r52535 = r52532 - r52534;
        double r52536 = r52531 * r52535;
        return r52536;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[x \cdot \left(1 - x \cdot 0.5\right)\]

  2. Final simplification0.0

    \[\leadsto x \cdot \left(1 - x \cdot 0.5\right)\]

Reproduce

herbie shell --seed 2019322 
(FPCore (x)
  :name "Numeric.SpecFunctions:log1p from math-functions-0.1.5.2, B"
  :precision binary64
  (* x (- 1 (* x 0.5))))