Average Error: 0.2 → 0.2
Time: 31.7s
Precision: 64
\[\left(x \cdot 27\right) \cdot y\]
↓
\[\left(x \cdot 27\right) \cdot y\]
\left(x \cdot 27\right) \cdot y
↓
\left(x \cdot 27\right) \cdot y
double f(double x, double y) {
        double r19068 = x;
        double r19069 = 27.0;
        double r19070 = r19068 * r19069;
        double r19071 = y;
        double r19072 = r19070 * r19071;
        return r19072;
}
↓
double f(double x, double y) {
        double r19073 = x;
        double r19074 = 27.0;
        double r19075 = r19073 * r19074;
        double r19076 = y;
        double r19077 = r19075 * r19076;
        return r19077;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.2

    \[\left(x \cdot 27\right) \cdot y\]

  2. Final simplification0.2

    \[\leadsto \left(x \cdot 27\right) \cdot y\]

Reproduce

herbie shell --seed 2019315 
(FPCore (x y)
  :name "Diagrams.Solve.Polynomial:cubForm  from diagrams-solve-0.1, F"
  :precision binary64
  (* (* x 27) y))