Average Error: 0.1 → 0
Time: 2.2s
Precision: 64
\[\left(d1 \cdot \left(\left(\left(\left(\left(d1 \cdot \left(d1 \cdot d1\right)\right) \cdot d1\right) \cdot d1\right) \cdot \left(d1 \cdot d1\right)\right) \cdot d1\right)\right) \cdot d1\]
\[{d1}^{10}\]
\left(d1 \cdot \left(\left(\left(\left(\left(d1 \cdot \left(d1 \cdot d1\right)\right) \cdot d1\right) \cdot d1\right) \cdot \left(d1 \cdot d1\right)\right) \cdot d1\right)\right) \cdot d1
{d1}^{10}
double f(double d1) {
        double r164146 = d1;
        double r164147 = r164146 * r164146;
        double r164148 = r164146 * r164147;
        double r164149 = r164148 * r164146;
        double r164150 = r164149 * r164146;
        double r164151 = r164150 * r164147;
        double r164152 = r164151 * r164146;
        double r164153 = r164146 * r164152;
        double r164154 = r164153 * r164146;
        return r164154;
}

double f(double d1) {
        double r164155 = d1;
        double r164156 = 10.0;
        double r164157 = pow(r164155, r164156);
        return r164157;
}

Error

Bits error versus d1

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.1
Target0
Herbie0
\[{d1}^{10}\]

Derivation

  1. Initial program 0.1

    \[\left(d1 \cdot \left(\left(\left(\left(\left(d1 \cdot \left(d1 \cdot d1\right)\right) \cdot d1\right) \cdot d1\right) \cdot \left(d1 \cdot d1\right)\right) \cdot d1\right)\right) \cdot d1\]
  2. Simplified0

    \[\leadsto \color{blue}{{d1}^{10}}\]
  3. Final simplification0

    \[\leadsto {d1}^{10}\]

Reproduce

herbie shell --seed 2019308 
(FPCore (d1)
  :name "FastMath test5"
  :precision binary64

  :herbie-target
  (pow d1 10)

  (* (* d1 (* (* (* (* (* d1 (* d1 d1)) d1) d1) (* d1 d1)) d1)) d1))