Average Error: 0 → 0
Time: 519.0ms
Precision: 64
\[\left(x \cdot 16\right) \cdot x\]
\[\left(x \cdot 16\right) \cdot x\]
\left(x \cdot 16\right) \cdot x
\left(x \cdot 16\right) \cdot x
double f(double x) {
        double r156276 = x;
        double r156277 = 16.0;
        double r156278 = r156276 * r156277;
        double r156279 = r156278 * r156276;
        return r156279;
}

double f(double x) {
        double r156280 = x;
        double r156281 = 16.0;
        double r156282 = r156280 * r156281;
        double r156283 = r156282 * r156280;
        return r156283;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0

    \[\left(x \cdot 16\right) \cdot x\]
  2. Final simplification0

    \[\leadsto \left(x \cdot 16\right) \cdot x\]

Reproduce

herbie shell --seed 2019308 
(FPCore (x)
  :name "Graphics.Rasterific.CubicBezier:isSufficientlyFlat from Rasterific-0.6.1"
  :precision binary64
  (* (* x 16) x))