Average Error: 0 → 0

Time: 593.0ms

Precision: 64

\[\left(\left(\left(x + x\right) + x\right) + x\right) + x\]

↓

\[x \cdot 5\]

\left(\left(\left(x + x\right) + x\right) + x\right) + x

↓

x \cdot 5

double f(double x) {
        double r87546 = x;
        double r87547 = r87546 + r87546;
        double r87548 = r87547 + r87546;
        double r87549 = r87548 + r87546;
        double r87550 = r87549 + r87546;
        return r87550;
}

↓

double f(double x) {
        double r87551 = x;
        double r87552 = 5.0;
        double r87553 = r87551 * r87552;
        return r87553;
}

Error

The X axis uses an exponential scale — Bits error versus `x`

Try it out

In
Out

Enter valid numbers for all inputs

Derivation

Initial program 0
\[\left(\left(\left(x + x\right) + x\right) + x\right) + x\]
Final simplification0
\[\leadsto x \cdot 5\]

Reproduce

herbie shell --seed 2019308 
(FPCore (x)
  :name "Main:i from "
  :precision binary64
  (+ (+ (+ (+ x x) x) x) x))