Average Error: 0.0 → 0.0
Time: 1.7s
Precision: 64
\[x \cdot \left(1 - x \cdot 0.5\right)\]
↓
\[x \cdot \left(1 - x \cdot 0.5\right)\]
x \cdot \left(1 - x \cdot 0.5\right)
↓
x \cdot \left(1 - x \cdot 0.5\right)
double f(double x) {
        double r37612 = x;
        double r37613 = 1.0;
        double r37614 = 0.5;
        double r37615 = r37612 * r37614;
        double r37616 = r37613 - r37615;
        double r37617 = r37612 * r37616;
        return r37617;
}
↓
double f(double x) {
        double r37618 = x;
        double r37619 = 1.0;
        double r37620 = 0.5;
        double r37621 = r37618 * r37620;
        double r37622 = r37619 - r37621;
        double r37623 = r37618 * r37622;
        return r37623;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[x \cdot \left(1 - x \cdot 0.5\right)\]

  2. Final simplification0.0

    \[\leadsto x \cdot \left(1 - x \cdot 0.5\right)\]

Reproduce

herbie shell --seed 2019308 
(FPCore (x)
  :name "Numeric.SpecFunctions:log1p from math-functions-0.1.5.2, B"
  :precision binary64
  (* x (- 1 (* x 0.5))))