Average Error: 0.1 → 0.1
Time: 7.8s
Precision: 64
\[x \cdot \left(y + z\right) + z \cdot 5\]
↓
\[x \cdot y + z \cdot \left(5 + x\right)\]
x \cdot \left(y + z\right) + z \cdot 5
↓
x \cdot y + z \cdot \left(5 + x\right)
double f(double x, double y, double z) {
        double r426106 = x;
        double r426107 = y;
        double r426108 = z;
        double r426109 = r426107 + r426108;
        double r426110 = r426106 * r426109;
        double r426111 = 5.0;
        double r426112 = r426108 * r426111;
        double r426113 = r426110 + r426112;
        return r426113;
}
↓
double f(double x, double y, double z) {
        double r426114 = x;
        double r426115 = y;
        double r426116 = r426114 * r426115;
        double r426117 = z;
        double r426118 = 5.0;
        double r426119 = r426118 + r426114;
        double r426120 = r426117 * r426119;
        double r426121 = r426116 + r426120;
        return r426121;
}

Error

Bits error versus x

Bits error versus y

Bits error versus z

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.1
Target0.1
Herbie0.1
\[\left(x + 5\right) \cdot z + x \cdot y\]

Derivation

  1. Initial program 0.1

    \[x \cdot \left(y + z\right) + z \cdot 5\]
  2. Using strategy rm

  3. Applied distribute-lft-in0.1

    \[\leadsto \color{blue}{\left(x \cdot y + x \cdot z\right)} + z \cdot 5\]

  4. Applied associate-+l+0.1

    \[\leadsto \color{blue}{x \cdot y + \left(x \cdot z + z \cdot 5\right)}\]

  5. Simplified0.1

    \[\leadsto x \cdot y + \color{blue}{z \cdot \left(5 + x\right)}\]

  6. Final simplification0.1

    \[\leadsto x \cdot y + z \cdot \left(5 + x\right)\]

Reproduce

herbie shell --seed 2019305 
(FPCore (x y z)
  :name "Graphics.Rendering.Plot.Render.Plot.Legend:renderLegendOutside from plot-0.2.3.4, C"
  :precision binary64

  :herbie-target
  (+ (* (+ x 5) z) (* x y))

  (+ (* x (+ y z)) (* z 5)))