Average Error: 58.8 → 0.5
Time: 12.6s
Precision: 64
\[-1.700000000000000122124532708767219446599 \cdot 10^{-4} \lt x\]
\[e^{x} - 1\]
\[{x}^{2} \cdot \left(\frac{1}{2} + x \cdot \frac{1}{6}\right) + x\]
e^{x} - 1
{x}^{2} \cdot \left(\frac{1}{2} + x \cdot \frac{1}{6}\right) + x
double f(double x) {
        double r92428 = x;
        double r92429 = exp(r92428);
        double r92430 = 1.0;
        double r92431 = r92429 - r92430;
        return r92431;
}

double f(double x) {
        double r92432 = x;
        double r92433 = 2.0;
        double r92434 = pow(r92432, r92433);
        double r92435 = 0.5;
        double r92436 = 0.16666666666666666;
        double r92437 = r92432 * r92436;
        double r92438 = r92435 + r92437;
        double r92439 = r92434 * r92438;
        double r92440 = r92439 + r92432;
        return r92440;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original58.8
Target0.5
Herbie0.5
\[x \cdot \left(\left(1 + \frac{x}{2}\right) + \frac{x \cdot x}{6}\right)\]

Derivation

  1. Initial program 58.8

    \[e^{x} - 1\]
  2. Taylor expanded around 0 0.5

    \[\leadsto \color{blue}{\frac{1}{2} \cdot {x}^{2} + \left(\frac{1}{6} \cdot {x}^{3} + x\right)}\]
  3. Simplified0.5

    \[\leadsto \color{blue}{{x}^{2} \cdot \left(\frac{1}{2} + x \cdot \frac{1}{6}\right) + x}\]
  4. Final simplification0.5

    \[\leadsto {x}^{2} \cdot \left(\frac{1}{2} + x \cdot \frac{1}{6}\right) + x\]

Reproduce

herbie shell --seed 2019305 
(FPCore (x)
  :name "expm1 (example 3.7)"
  :precision binary64
  :pre (< -1.7e-4 x)

  :herbie-target
  (* x (+ (+ 1 (/ x 2)) (/ (* x x) 6)))

  (- (exp x) 1))