Average Error: 0.0 → 0.0
Time: 884.0ms
Precision: 64
\[\frac{x \cdot y}{2}\]
\[x \cdot \frac{y}{2}\]
\frac{x \cdot y}{2}
x \cdot \frac{y}{2}
double f(double x, double y) {
        double r101212 = x;
        double r101213 = y;
        double r101214 = r101212 * r101213;
        double r101215 = 2.0;
        double r101216 = r101214 / r101215;
        return r101216;
}

double f(double x, double y) {
        double r101217 = x;
        double r101218 = y;
        double r101219 = 2.0;
        double r101220 = r101218 / r101219;
        double r101221 = r101217 * r101220;
        return r101221;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[\frac{x \cdot y}{2}\]
  2. Using strategy rm
  3. Applied *-un-lft-identity0.0

    \[\leadsto \frac{x \cdot y}{\color{blue}{1 \cdot 2}}\]
  4. Applied times-frac0.0

    \[\leadsto \color{blue}{\frac{x}{1} \cdot \frac{y}{2}}\]
  5. Simplified0.0

    \[\leadsto \color{blue}{x} \cdot \frac{y}{2}\]
  6. Final simplification0.0

    \[\leadsto x \cdot \frac{y}{2}\]

Reproduce

herbie shell --seed 2019304 
(FPCore (x y)
  :name "Numeric.Interval.Internal:scale from intervals-0.7.1, B"
  :precision binary64
  (/ (* x y) 2))