Average Error: 0.0 → 0.0
Time: 7.7s
Precision: 64
\[e^{\left(x \cdot y\right) \cdot y}\]
\[e^{\left(x \cdot y\right) \cdot y}\]
e^{\left(x \cdot y\right) \cdot y}
e^{\left(x \cdot y\right) \cdot y}
double f(double x, double y) {
        double r149284 = x;
        double r149285 = y;
        double r149286 = r149284 * r149285;
        double r149287 = r149286 * r149285;
        double r149288 = exp(r149287);
        return r149288;
}

double f(double x, double y) {
        double r149289 = x;
        double r149290 = y;
        double r149291 = r149289 * r149290;
        double r149292 = r149291 * r149290;
        double r149293 = exp(r149292);
        return r149293;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[e^{\left(x \cdot y\right) \cdot y}\]
  2. Final simplification0.0

    \[\leadsto e^{\left(x \cdot y\right) \cdot y}\]

Reproduce

herbie shell --seed 2019303 +o rules:numerics
(FPCore (x y)
  :name "Data.Random.Distribution.Normal:normalF from random-fu-0.2.6.2"
  :precision binary64
  (exp (* (* x y) y)))