Average Error: 0.0 → 0.0
Time: 8.4s
Precision: 64
\[e^{\left(x \cdot y\right) \cdot y}\]
\[e^{\left(x \cdot y\right) \cdot y}\]
e^{\left(x \cdot y\right) \cdot y}
e^{\left(x \cdot y\right) \cdot y}
double f(double x, double y) {
        double r825871 = x;
        double r825872 = y;
        double r825873 = r825871 * r825872;
        double r825874 = r825873 * r825872;
        double r825875 = exp(r825874);
        return r825875;
}

double f(double x, double y) {
        double r825876 = x;
        double r825877 = y;
        double r825878 = r825876 * r825877;
        double r825879 = r825878 * r825877;
        double r825880 = exp(r825879);
        return r825880;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[e^{\left(x \cdot y\right) \cdot y}\]
  2. Final simplification0.0

    \[\leadsto e^{\left(x \cdot y\right) \cdot y}\]

Reproduce

herbie shell --seed 2019303 
(FPCore (x y)
  :name "Data.Random.Distribution.Normal:normalF from random-fu-0.2.6.2"
  :precision binary64
  (exp (* (* x y) y)))