Average Error: 0.0 → 0.0
Time: 5.7s
Precision: 64
\[x \cdot e^{y \cdot y}\]
↓
\[x \cdot e^{y \cdot y}\]
x \cdot e^{y \cdot y}
↓
x \cdot e^{y \cdot y}
double f(double x, double y) {
        double r602301 = x;
        double r602302 = y;
        double r602303 = r602302 * r602302;
        double r602304 = exp(r602303);
        double r602305 = r602301 * r602304;
        return r602305;
}
↓
double f(double x, double y) {
        double r602306 = x;
        double r602307 = y;
        double r602308 = r602307 * r602307;
        double r602309 = exp(r602308);
        double r602310 = r602306 * r602309;
        return r602310;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.0
Target0.0
Herbie0.0
\[x \cdot {\left(e^{y}\right)}^{y}\]

Derivation

  1. Initial program 0.0

    \[x \cdot e^{y \cdot y}\]

  2. Final simplification0.0

    \[\leadsto x \cdot e^{y \cdot y}\]

Reproduce

herbie shell --seed 2019235 
(FPCore (x y)
  :name "Data.Number.Erf:$dmerfcx from erf-2.0.0.0"
  :precision binary64

  :herbie-target
  (* x (pow (exp y) y))

  (* x (exp (* y y))))