x \cdot \left(\frac{y}{z} - \frac{t}{1 - z}\right)\begin{array}{l}
\mathbf{if}\;\frac{y}{z} - \frac{t}{1 - z} = -\infty:\\
\;\;\;\;\frac{x \cdot \left(y \cdot \left(1 - z\right) - z \cdot t\right)}{z \cdot \left(1 - z\right)}\\
\mathbf{elif}\;\frac{y}{z} - \frac{t}{1 - z} \le -3.646424278606502678263957997837655215247 \cdot 10^{-233}:\\
\;\;\;\;x \cdot \left(\frac{y}{z} - \frac{1}{\frac{1 - z}{t}}\right)\\
\mathbf{elif}\;\frac{y}{z} - \frac{t}{1 - z} \le 1.266911076549827575105216650109113541904 \cdot 10^{-282}:\\
\;\;\;\;\left(\frac{1}{z} + 1\right) \cdot \frac{t \cdot x}{z} + \frac{x \cdot y}{z}\\
\mathbf{elif}\;\frac{y}{z} - \frac{t}{1 - z} \le 3.632482779017283391313108001321509173255 \cdot 10^{260}:\\
\;\;\;\;x \cdot \left(\frac{y}{z} - \frac{1}{\frac{1 - z}{t}}\right)\\
\mathbf{else}:\\
\;\;\;\;\frac{x \cdot \left(y \cdot \left(1 - z\right) - z \cdot t\right)}{z \cdot \left(1 - z\right)}\\
\end{array}double f(double x, double y, double z, double t) {
double r1606005 = x;
double r1606006 = y;
double r1606007 = z;
double r1606008 = r1606006 / r1606007;
double r1606009 = t;
double r1606010 = 1.0;
double r1606011 = r1606010 - r1606007;
double r1606012 = r1606009 / r1606011;
double r1606013 = r1606008 - r1606012;
double r1606014 = r1606005 * r1606013;
return r1606014;
}
double f(double x, double y, double z, double t) {
double r1606015 = y;
double r1606016 = z;
double r1606017 = r1606015 / r1606016;
double r1606018 = t;
double r1606019 = 1.0;
double r1606020 = r1606019 - r1606016;
double r1606021 = r1606018 / r1606020;
double r1606022 = r1606017 - r1606021;
double r1606023 = -inf.0;
bool r1606024 = r1606022 <= r1606023;
double r1606025 = x;
double r1606026 = r1606015 * r1606020;
double r1606027 = r1606016 * r1606018;
double r1606028 = r1606026 - r1606027;
double r1606029 = r1606025 * r1606028;
double r1606030 = r1606016 * r1606020;
double r1606031 = r1606029 / r1606030;
double r1606032 = -3.6464242786065027e-233;
bool r1606033 = r1606022 <= r1606032;
double r1606034 = 1.0;
double r1606035 = r1606020 / r1606018;
double r1606036 = r1606034 / r1606035;
double r1606037 = r1606017 - r1606036;
double r1606038 = r1606025 * r1606037;
double r1606039 = 1.2669110765498276e-282;
bool r1606040 = r1606022 <= r1606039;
double r1606041 = r1606019 / r1606016;
double r1606042 = r1606041 + r1606034;
double r1606043 = r1606018 * r1606025;
double r1606044 = r1606043 / r1606016;
double r1606045 = r1606042 * r1606044;
double r1606046 = r1606025 * r1606015;
double r1606047 = r1606046 / r1606016;
double r1606048 = r1606045 + r1606047;
double r1606049 = 3.6324827790172834e+260;
bool r1606050 = r1606022 <= r1606049;
double r1606051 = r1606050 ? r1606038 : r1606031;
double r1606052 = r1606040 ? r1606048 : r1606051;
double r1606053 = r1606033 ? r1606038 : r1606052;
double r1606054 = r1606024 ? r1606031 : r1606053;
return r1606054;
}




Bits error versus x




Bits error versus y




Bits error versus z




Bits error versus t
Results
| Original | 4.7 |
|---|---|
| Target | 4.4 |
| Herbie | 0.4 |
if (- (/ y z) (/ t (- 1.0 z))) < -inf.0 or 3.6324827790172834e+260 < (- (/ y z) (/ t (- 1.0 z))) Initial program 43.0
rmApplied frac-sub44.0
Applied associate-*r/1.3
if -inf.0 < (- (/ y z) (/ t (- 1.0 z))) < -3.6464242786065027e-233 or 1.2669110765498276e-282 < (- (/ y z) (/ t (- 1.0 z))) < 3.6324827790172834e+260Initial program 0.2
rmApplied clear-num0.3
if -3.6464242786065027e-233 < (- (/ y z) (/ t (- 1.0 z))) < 1.2669110765498276e-282Initial program 12.4
Taylor expanded around inf 0.6
Simplified0.6
Final simplification0.4
herbie shell --seed 2019235
(FPCore (x y z t)
:name "Numeric.SpecFunctions:invIncompleteBetaWorker from math-functions-0.1.5.2, C"
:precision binary64
:herbie-target
(if (< (* x (- (/ y z) (/ t (- 1 z)))) -7.62322630331204244e-196) (* x (- (/ y z) (* t (/ 1 (- 1 z))))) (if (< (* x (- (/ y z) (/ t (- 1 z)))) 1.41339449277023022e-211) (+ (/ (* y x) z) (- (/ (* t x) (- 1 z)))) (* x (- (/ y z) (* t (/ 1 (- 1 z)))))))
(* x (- (/ y z) (/ t (- 1 z)))))