Average Error: 0.6 → 0.5
Time: 10.2s
Precision: 64
\[\frac{e^{a}}{e^{a} + e^{b}}\]
\[e^{a - \log \left(e^{a} + e^{b}\right)}\]
\frac{e^{a}}{e^{a} + e^{b}}
e^{a - \log \left(e^{a} + e^{b}\right)}
double f(double a, double b) {
        double r95408 = a;
        double r95409 = exp(r95408);
        double r95410 = b;
        double r95411 = exp(r95410);
        double r95412 = r95409 + r95411;
        double r95413 = r95409 / r95412;
        return r95413;
}

double f(double a, double b) {
        double r95414 = a;
        double r95415 = exp(r95414);
        double r95416 = b;
        double r95417 = exp(r95416);
        double r95418 = r95415 + r95417;
        double r95419 = log(r95418);
        double r95420 = r95414 - r95419;
        double r95421 = exp(r95420);
        return r95421;
}

Error

Bits error versus a

Bits error versus b

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.6
Target0.0
Herbie0.5
\[\frac{1}{1 + e^{b - a}}\]

Derivation

  1. Initial program 0.6

    \[\frac{e^{a}}{e^{a} + e^{b}}\]
  2. Using strategy rm
  3. Applied add-exp-log0.6

    \[\leadsto \frac{e^{a}}{\color{blue}{e^{\log \left(e^{a} + e^{b}\right)}}}\]
  4. Applied div-exp0.5

    \[\leadsto \color{blue}{e^{a - \log \left(e^{a} + e^{b}\right)}}\]
  5. Final simplification0.5

    \[\leadsto e^{a - \log \left(e^{a} + e^{b}\right)}\]

Reproduce

herbie shell --seed 2019208 
(FPCore (a b)
  :name "Quotient of sum of exps"
  :precision binary64

  :herbie-target
  (/ 1 (+ 1 (exp (- b a))))

  (/ (exp a) (+ (exp a) (exp b))))