0.5 \cdot \sqrt{2 \cdot \left(\sqrt{re \cdot re + im \cdot im} - re\right)}\sqrt{2 \cdot \left(\mathsf{hypot}\left(re, im\right) - re\right)} \cdot 0.5double f(double re, double im) {
double r829120 = 0.5;
double r829121 = 2.0;
double r829122 = re;
double r829123 = r829122 * r829122;
double r829124 = im;
double r829125 = r829124 * r829124;
double r829126 = r829123 + r829125;
double r829127 = sqrt(r829126);
double r829128 = r829127 - r829122;
double r829129 = r829121 * r829128;
double r829130 = sqrt(r829129);
double r829131 = r829120 * r829130;
return r829131;
}
double f(double re, double im) {
double r829132 = 2.0;
double r829133 = re;
double r829134 = im;
double r829135 = hypot(r829133, r829134);
double r829136 = r829135 - r829133;
double r829137 = r829132 * r829136;
double r829138 = sqrt(r829137);
double r829139 = 0.5;
double r829140 = r829138 * r829139;
return r829140;
}



Bits error versus re



Bits error versus im
Results
Initial program 38.8
Simplified13.5
Final simplification13.5
herbie shell --seed 2019200 +o rules:numerics
(FPCore (re im)
:name "math.sqrt on complex, imaginary part, im greater than 0 branch"
(* 0.5 (sqrt (* 2.0 (- (sqrt (+ (* re re) (* im im))) re)))))