Average Error: 39.1 → 0.0
Time: 6.1s
Precision: 64
\[\left(x + 1\right) \cdot \left(x + 1\right) - 1\]
\[x \cdot \left(2 + x\right)\]
\left(x + 1\right) \cdot \left(x + 1\right) - 1
x \cdot \left(2 + x\right)
double f(double x) {
        double r9703 = x;
        double r9704 = 1.0;
        double r9705 = r9703 + r9704;
        double r9706 = r9705 * r9705;
        double r9707 = r9706 - r9704;
        return r9707;
}

double f(double x) {
        double r9708 = x;
        double r9709 = 2.0;
        double r9710 = r9709 + r9708;
        double r9711 = r9708 * r9710;
        return r9711;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 39.1

    \[\left(x + 1\right) \cdot \left(x + 1\right) - 1\]
  2. Taylor expanded around 0 0.0

    \[\leadsto \color{blue}{{x}^{2} + 2 \cdot x}\]
  3. Simplified0.0

    \[\leadsto \color{blue}{x \cdot \left(2 + x\right)}\]
  4. Final simplification0.0

    \[\leadsto x \cdot \left(2 + x\right)\]

Reproduce

herbie shell --seed 2019199 +o rules:numerics
(FPCore (x)
  :name "Expanding a square"
  (- (* (+ x 1.0) (+ x 1.0)) 1.0))