Average Error: 0 → 0
Time: 1.1s
Precision: 64
\[\left(x \cdot 16\right) \cdot x\]
\[\left(x \cdot 16\right) \cdot x\]
\left(x \cdot 16\right) \cdot x
\left(x \cdot 16\right) \cdot x
double f(double x) {
        double r106913 = x;
        double r106914 = 16.0;
        double r106915 = r106913 * r106914;
        double r106916 = r106915 * r106913;
        return r106916;
}

double f(double x) {
        double r106917 = x;
        double r106918 = 16.0;
        double r106919 = r106917 * r106918;
        double r106920 = r106919 * r106917;
        return r106920;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0

    \[\left(x \cdot 16\right) \cdot x\]
  2. Final simplification0

    \[\leadsto \left(x \cdot 16\right) \cdot x\]

Reproduce

herbie shell --seed 2019199 +o rules:numerics
(FPCore (x)
  :name "Graphics.Rasterific.CubicBezier:isSufficientlyFlat from Rasterific-0.6.1"
  (* (* x 16.0) x))