Average Error: 0.0 → 0.0
Time: 2.9s
Precision: 64
\[x \cdot \left(1 - x \cdot 0.5\right)\]
↓
\[x \cdot \left(1 - x \cdot 0.5\right)\]
x \cdot \left(1 - x \cdot 0.5\right)
↓
x \cdot \left(1 - x \cdot 0.5\right)
double f(double x) {
        double r52094 = x;
        double r52095 = 1.0;
        double r52096 = 0.5;
        double r52097 = r52094 * r52096;
        double r52098 = r52095 - r52097;
        double r52099 = r52094 * r52098;
        return r52099;
}
↓
double f(double x) {
        double r52100 = x;
        double r52101 = 1.0;
        double r52102 = 0.5;
        double r52103 = r52100 * r52102;
        double r52104 = r52101 - r52103;
        double r52105 = r52100 * r52104;
        return r52105;
}

Error

Bits error versus x

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Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[x \cdot \left(1 - x \cdot 0.5\right)\]

  2. Final simplification0.0

    \[\leadsto x \cdot \left(1 - x \cdot 0.5\right)\]

Reproduce

herbie shell --seed 2019198 +o rules:numerics
(FPCore (x)
  :name "Numeric.SpecFunctions:log1p from math-functions-0.1.5.2, B"
  (* x (- 1.0 (* x 0.5))))