Average Error: 0.1 → 0
Time: 2.5s
Precision: 64
\[\left(\left(d1 \cdot d1\right) \cdot d1\right) \cdot d1\]
↓
\[{d1}^{4}\]
\left(\left(d1 \cdot d1\right) \cdot d1\right) \cdot d1
↓
{d1}^{4}
double f(double d1) {
        double r85470 = d1;
        double r85471 = r85470 * r85470;
        double r85472 = r85471 * r85470;
        double r85473 = r85472 * r85470;
        return r85473;
}
↓
double f(double d1) {
        double r85474 = d1;
        double r85475 = 4.0;
        double r85476 = pow(r85474, r85475);
        return r85476;
}

Error

Bits error versus d1

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.1
Target0
Herbie0
\[{d1}^{4}\]

Derivation

  1. Initial program 0.1

    \[\left(\left(d1 \cdot d1\right) \cdot d1\right) \cdot d1\]

  2. Simplified0

    \[\leadsto \color{blue}{{d1}^{4}}\]

  3. Final simplification0

    \[\leadsto {d1}^{4}\]

Reproduce

herbie shell --seed 2019196 +o rules:numerics
(FPCore (d1)
  :name "FastMath repmul"

  :herbie-target
  (pow d1 4.0)

  (* (* (* d1 d1) d1) d1))