Average Error: 5.6 → 0
Time: 4.3s
Precision: 64
\[e^{\log a + \log b}\]
\[b \cdot a\]
e^{\log a + \log b}
b \cdot a
double f(double a, double b) {
        double r77936 = a;
        double r77937 = log(r77936);
        double r77938 = b;
        double r77939 = log(r77938);
        double r77940 = r77937 + r77939;
        double r77941 = exp(r77940);
        return r77941;
}

double f(double a, double b) {
        double r77942 = b;
        double r77943 = a;
        double r77944 = r77942 * r77943;
        return r77944;
}

Error

Bits error versus a

Bits error versus b

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original5.6
Target0
Herbie0
\[a \cdot b\]

Derivation

  1. Initial program 5.6

    \[e^{\log a + \log b}\]
  2. Simplified0

    \[\leadsto \color{blue}{b \cdot a}\]
  3. Final simplification0

    \[\leadsto b \cdot a\]

Reproduce

herbie shell --seed 2019195 +o rules:numerics
(FPCore (a b)
  :name "Exp of sum of logs"

  :herbie-target
  (* a b)

  (exp (+ (log a) (log b))))