Average Error: 5.6 → 0
Time: 4.4s
Precision: 64
\[e^{\log a + \log b}\]
\[a \cdot b\]
e^{\log a + \log b}
a \cdot b
double f(double a, double b) {
        double r103443 = a;
        double r103444 = log(r103443);
        double r103445 = b;
        double r103446 = log(r103445);
        double r103447 = r103444 + r103446;
        double r103448 = exp(r103447);
        return r103448;
}

double f(double a, double b) {
        double r103449 = a;
        double r103450 = b;
        double r103451 = r103449 * r103450;
        return r103451;
}

Error

Bits error versus a

Bits error versus b

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original5.6
Target0
Herbie0
\[a \cdot b\]

Derivation

  1. Initial program 5.6

    \[e^{\log a + \log b}\]
  2. Simplified0

    \[\leadsto \color{blue}{a \cdot b}\]
  3. Final simplification0

    \[\leadsto a \cdot b\]

Reproduce

herbie shell --seed 2019195 +o rules:numerics
(FPCore (a b)
  :name "Exp of sum of logs"

  :herbie-target
  (* a b)

  (exp (+ (log a) (log b))))