Average Error: 60.4 → 3.2
Time: 32.8s
Precision: 64
\[-1 \lt \varepsilon \land \varepsilon \lt 1\]
\[\frac{\varepsilon \cdot \left(e^{\left(a + b\right) \cdot \varepsilon} - 1\right)}{\left(e^{a \cdot \varepsilon} - 1\right) \cdot \left(e^{b \cdot \varepsilon} - 1\right)}\]
\[\frac{1}{b} + \frac{1}{a}\]
\frac{\varepsilon \cdot \left(e^{\left(a + b\right) \cdot \varepsilon} - 1\right)}{\left(e^{a \cdot \varepsilon} - 1\right) \cdot \left(e^{b \cdot \varepsilon} - 1\right)}
\frac{1}{b} + \frac{1}{a}
double f(double a, double b, double eps) {
        double r80024 = eps;
        double r80025 = a;
        double r80026 = b;
        double r80027 = r80025 + r80026;
        double r80028 = r80027 * r80024;
        double r80029 = exp(r80028);
        double r80030 = 1.0;
        double r80031 = r80029 - r80030;
        double r80032 = r80024 * r80031;
        double r80033 = r80025 * r80024;
        double r80034 = exp(r80033);
        double r80035 = r80034 - r80030;
        double r80036 = r80026 * r80024;
        double r80037 = exp(r80036);
        double r80038 = r80037 - r80030;
        double r80039 = r80035 * r80038;
        double r80040 = r80032 / r80039;
        return r80040;
}

double f(double a, double b, double __attribute__((unused)) eps) {
        double r80041 = 1.0;
        double r80042 = b;
        double r80043 = r80041 / r80042;
        double r80044 = a;
        double r80045 = r80041 / r80044;
        double r80046 = r80043 + r80045;
        return r80046;
}

Error

Bits error versus a

Bits error versus b

Bits error versus eps

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original60.4
Target15.1
Herbie3.2
\[\frac{a + b}{a \cdot b}\]

Derivation

  1. Initial program 60.4

    \[\frac{\varepsilon \cdot \left(e^{\left(a + b\right) \cdot \varepsilon} - 1\right)}{\left(e^{a \cdot \varepsilon} - 1\right) \cdot \left(e^{b \cdot \varepsilon} - 1\right)}\]
  2. Taylor expanded around 0 58.2

    \[\leadsto \frac{\varepsilon \cdot \left(e^{\left(a + b\right) \cdot \varepsilon} - 1\right)}{\color{blue}{\left(\frac{1}{2} \cdot \left({a}^{2} \cdot {\varepsilon}^{2}\right) + \left(\frac{1}{6} \cdot \left({a}^{3} \cdot {\varepsilon}^{3}\right) + a \cdot \varepsilon\right)\right)} \cdot \left(e^{b \cdot \varepsilon} - 1\right)}\]
  3. Simplified58.2

    \[\leadsto \frac{\varepsilon \cdot \left(e^{\left(a + b\right) \cdot \varepsilon} - 1\right)}{\color{blue}{\mathsf{fma}\left(a \cdot a, \frac{1}{2} \cdot \left(\varepsilon \cdot \varepsilon\right), \mathsf{fma}\left({\varepsilon}^{3}, \frac{1}{6} \cdot {a}^{3}, \varepsilon \cdot a\right)\right)} \cdot \left(e^{b \cdot \varepsilon} - 1\right)}\]
  4. Taylor expanded around 0 3.2

    \[\leadsto \color{blue}{\frac{1}{a} + \frac{1}{b}}\]
  5. Simplified3.2

    \[\leadsto \color{blue}{\frac{1}{b} + \frac{1}{a}}\]
  6. Final simplification3.2

    \[\leadsto \frac{1}{b} + \frac{1}{a}\]

Reproduce

herbie shell --seed 2019194 +o rules:numerics
(FPCore (a b eps)
  :name "expq3 (problem 3.4.2)"
  :pre (and (< -1.0 eps) (< eps 1.0))

  :herbie-target
  (/ (+ a b) (* a b))

  (/ (* eps (- (exp (* (+ a b) eps)) 1.0)) (* (- (exp (* a eps)) 1.0) (- (exp (* b eps)) 1.0))))