Average Error: 0.0 → 0.0
Time: 4.3s
Precision: 64
\[0.0 \le x \le 2\]
\[x + x \cdot x\]
\[x \cdot x + x\]
x + x \cdot x
x \cdot x + x
double f(double x) {
        double r57040 = x;
        double r57041 = r57040 * r57040;
        double r57042 = r57040 + r57041;
        return r57042;
}

double f(double x) {
        double r57043 = x;
        double r57044 = r57043 * r57043;
        double r57045 = r57044 + r57043;
        return r57045;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.0
Target0.0
Herbie0.0
\[\left(1 + x\right) \cdot x\]

Derivation

  1. Initial program 0.0

    \[x + x \cdot x\]
  2. Final simplification0.0

    \[\leadsto x \cdot x + x\]

Reproduce

herbie shell --seed 2019194 +o rules:numerics
(FPCore (x)
  :name "Expression 2, p15"
  :pre (<= 0.0 x 2.0)

  :herbie-target
  (* (+ 1.0 x) x)

  (+ x (* x x)))