Average Error: 0.3 → 0.3
Time: 7.7s
Precision: 64
\[\left(x \cdot 27\right) \cdot y\]
↓
\[\left(x \cdot 27\right) \cdot y\]
\left(x \cdot 27\right) \cdot y
↓
\left(x \cdot 27\right) \cdot y
double f(double x, double y) {
        double r108809 = x;
        double r108810 = 27.0;
        double r108811 = r108809 * r108810;
        double r108812 = y;
        double r108813 = r108811 * r108812;
        return r108813;
}
↓
double f(double x, double y) {
        double r108814 = x;
        double r108815 = 27.0;
        double r108816 = r108814 * r108815;
        double r108817 = y;
        double r108818 = r108816 * r108817;
        return r108818;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.3

    \[\left(x \cdot 27\right) \cdot y\]

  2. Final simplification0.3

    \[\leadsto \left(x \cdot 27\right) \cdot y\]

Reproduce

herbie shell --seed 2019194 +o rules:numerics
(FPCore (x y)
  :name "Diagrams.Solve.Polynomial:cubForm  from diagrams-solve-0.1, F"
  (* (* x 27.0) y))