Average Error: 5.7 → 0
Time: 4.3s
Precision: 64
\[e^{\log a + \log b}\]
\[a \cdot b\]
e^{\log a + \log b}
a \cdot b
double f(double a, double b) {
        double r61568 = a;
        double r61569 = log(r61568);
        double r61570 = b;
        double r61571 = log(r61570);
        double r61572 = r61569 + r61571;
        double r61573 = exp(r61572);
        return r61573;
}

double f(double a, double b) {
        double r61574 = a;
        double r61575 = b;
        double r61576 = r61574 * r61575;
        return r61576;
}

Error

Bits error versus a

Bits error versus b

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original5.7
Target0
Herbie0
\[a \cdot b\]

Derivation

  1. Initial program 5.7

    \[e^{\log a + \log b}\]
  2. Simplified0

    \[\leadsto \color{blue}{a \cdot b}\]
  3. Final simplification0

    \[\leadsto a \cdot b\]

Reproduce

herbie shell --seed 2019179 +o rules:numerics
(FPCore (a b)
  :name "Exp of sum of logs"

  :herbie-target
  (* a b)

  (exp (+ (log a) (log b))))