Average Error: 0.1 → 0
Time: 3.3s
Precision: 64
\[\left(d1 \cdot \left(\left(\left(\left(\left(d1 \cdot \left(d1 \cdot d1\right)\right) \cdot d1\right) \cdot d1\right) \cdot \left(d1 \cdot d1\right)\right) \cdot d1\right)\right) \cdot d1\]
↓
\[{d1}^{10}\]
\left(d1 \cdot \left(\left(\left(\left(\left(d1 \cdot \left(d1 \cdot d1\right)\right) \cdot d1\right) \cdot d1\right) \cdot \left(d1 \cdot d1\right)\right) \cdot d1\right)\right) \cdot d1
↓
{d1}^{10}
double f(double d1) {
        double r186518 = d1;
        double r186519 = r186518 * r186518;
        double r186520 = r186518 * r186519;
        double r186521 = r186520 * r186518;
        double r186522 = r186521 * r186518;
        double r186523 = r186522 * r186519;
        double r186524 = r186523 * r186518;
        double r186525 = r186518 * r186524;
        double r186526 = r186525 * r186518;
        return r186526;
}
↓
double f(double d1) {
        double r186527 = d1;
        double r186528 = 10.0;
        double r186529 = pow(r186527, r186528);
        return r186529;
}

Error

Bits error versus d1

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.1
Target0
Herbie0
\[{d1}^{10}\]

Derivation

  1. Initial program 0.1

    \[\left(d1 \cdot \left(\left(\left(\left(\left(d1 \cdot \left(d1 \cdot d1\right)\right) \cdot d1\right) \cdot d1\right) \cdot \left(d1 \cdot d1\right)\right) \cdot d1\right)\right) \cdot d1\]

  2. Simplified0

    \[\leadsto \color{blue}{{d1}^{10}}\]

  3. Final simplification0

    \[\leadsto {d1}^{10}\]

Reproduce

herbie shell --seed 2019179 +o rules:numerics
(FPCore (d1)
  :name "FastMath test5"

  :herbie-target
  (pow d1 10.0)

  (* (* d1 (* (* (* (* (* d1 (* d1 d1)) d1) d1) (* d1 d1)) d1)) d1))