Average Error: 0.3 → 0.3
Time: 11.2s
Precision: 64
\[\left(x \cdot 27\right) \cdot y\]
↓
\[\left(x \cdot 27\right) \cdot y\]
\left(x \cdot 27\right) \cdot y
↓
\left(x \cdot 27\right) \cdot y
double f(double x, double y) {
        double r216390 = x;
        double r216391 = 27.0;
        double r216392 = r216390 * r216391;
        double r216393 = y;
        double r216394 = r216392 * r216393;
        return r216394;
}
↓
double f(double x, double y) {
        double r216395 = x;
        double r216396 = 27.0;
        double r216397 = r216395 * r216396;
        double r216398 = y;
        double r216399 = r216397 * r216398;
        return r216399;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.3

    \[\left(x \cdot 27\right) \cdot y\]

  2. Final simplification0.3

    \[\leadsto \left(x \cdot 27\right) \cdot y\]

Reproduce

herbie shell --seed 2019179 
(FPCore (x y)
  :name "Diagrams.Solve.Polynomial:cubForm  from diagrams-solve-0.1, F"
  (* (* x 27.0) y))