Average Error: 0.2 → 0.0
Time: 12.8s
Precision: 64
\[\left(d1 \cdot 10 + d1 \cdot d2\right) + d1 \cdot 20\]
\[\left(d2 + \left(20 + 10\right)\right) \cdot d1\]
\left(d1 \cdot 10 + d1 \cdot d2\right) + d1 \cdot 20
\left(d2 + \left(20 + 10\right)\right) \cdot d1
double f(double d1, double d2) {
        double r10295748 = d1;
        double r10295749 = 10.0;
        double r10295750 = r10295748 * r10295749;
        double r10295751 = d2;
        double r10295752 = r10295748 * r10295751;
        double r10295753 = r10295750 + r10295752;
        double r10295754 = 20.0;
        double r10295755 = r10295748 * r10295754;
        double r10295756 = r10295753 + r10295755;
        return r10295756;
}

double f(double d1, double d2) {
        double r10295757 = d2;
        double r10295758 = 20.0;
        double r10295759 = 10.0;
        double r10295760 = r10295758 + r10295759;
        double r10295761 = r10295757 + r10295760;
        double r10295762 = d1;
        double r10295763 = r10295761 * r10295762;
        return r10295763;
}

Error

Bits error versus d1

Bits error versus d2

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.2
Target0.0
Herbie0.0
\[d1 \cdot \left(30 + d2\right)\]

Derivation

  1. Initial program 0.2

    \[\left(d1 \cdot 10 + d1 \cdot d2\right) + d1 \cdot 20\]
  2. Simplified0.0

    \[\leadsto \color{blue}{\left(\left(10 + 20\right) + d2\right) \cdot d1}\]
  3. Final simplification0.0

    \[\leadsto \left(d2 + \left(20 + 10\right)\right) \cdot d1\]

Reproduce

herbie shell --seed 2019179 +o rules:numerics
(FPCore (d1 d2)
  :name "FastMath test2"

  :herbie-target
  (* d1 (+ 30.0 d2))

  (+ (+ (* d1 10.0) (* d1 d2)) (* d1 20.0)))