Average Error: 0.3 → 0.3
Time: 10.6s
Precision: 64
\[\left(x \cdot 27\right) \cdot y\]
\[\left(x \cdot 27\right) \cdot y\]
\left(x \cdot 27\right) \cdot y
\left(x \cdot 27\right) \cdot y
double f(double x, double y) {
        double r9540057 = x;
        double r9540058 = 27.0;
        double r9540059 = r9540057 * r9540058;
        double r9540060 = y;
        double r9540061 = r9540059 * r9540060;
        return r9540061;
}

double f(double x, double y) {
        double r9540062 = x;
        double r9540063 = 27.0;
        double r9540064 = r9540062 * r9540063;
        double r9540065 = y;
        double r9540066 = r9540064 * r9540065;
        return r9540066;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.3

    \[\left(x \cdot 27\right) \cdot y\]
  2. Final simplification0.3

    \[\leadsto \left(x \cdot 27\right) \cdot y\]

Reproduce

herbie shell --seed 2019179 +o rules:numerics
(FPCore (x y)
  :name "Diagrams.Solve.Polynomial:cubForm  from diagrams-solve-0.1, F"
  (* (* x 27.0) y))