Average Error: 0.0 → 0.0
Time: 3.2s
Precision: 64
\[x \cdot \left(1 - x \cdot 0.5\right)\]
↓
\[\left(1 - x \cdot 0.5\right) \cdot x\]
x \cdot \left(1 - x \cdot 0.5\right)
↓
\left(1 - x \cdot 0.5\right) \cdot x
double f(double x) {
        double r2316358 = x;
        double r2316359 = 1.0;
        double r2316360 = 0.5;
        double r2316361 = r2316358 * r2316360;
        double r2316362 = r2316359 - r2316361;
        double r2316363 = r2316358 * r2316362;
        return r2316363;
}
↓
double f(double x) {
        double r2316364 = 1.0;
        double r2316365 = x;
        double r2316366 = 0.5;
        double r2316367 = r2316365 * r2316366;
        double r2316368 = r2316364 - r2316367;
        double r2316369 = r2316368 * r2316365;
        return r2316369;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[x \cdot \left(1 - x \cdot 0.5\right)\]

  2. Final simplification0.0

    \[\leadsto \left(1 - x \cdot 0.5\right) \cdot x\]

Reproduce

herbie shell --seed 2019179 +o rules:numerics
(FPCore (x)
  :name "Numeric.SpecFunctions:log1p from math-functions-0.1.5.2, B"
  (* x (- 1.0 (* x 0.5))))