Average Error: 0.3 → 0.3
Time: 12.4s
Precision: 64
\[\left(x \cdot 27\right) \cdot y\]
↓
\[\left(x \cdot 27\right) \cdot y\]
\left(x \cdot 27\right) \cdot y
↓
\left(x \cdot 27\right) \cdot y
double f(double x, double y) {
        double r8705072 = x;
        double r8705073 = 27.0;
        double r8705074 = r8705072 * r8705073;
        double r8705075 = y;
        double r8705076 = r8705074 * r8705075;
        return r8705076;
}
↓
double f(double x, double y) {
        double r8705077 = x;
        double r8705078 = 27.0;
        double r8705079 = r8705077 * r8705078;
        double r8705080 = y;
        double r8705081 = r8705079 * r8705080;
        return r8705081;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.3

    \[\left(x \cdot 27\right) \cdot y\]

  2. Final simplification0.3

    \[\leadsto \left(x \cdot 27\right) \cdot y\]

Reproduce

herbie shell --seed 2019179 
(FPCore (x y)
  :name "Diagrams.Solve.Polynomial:cubForm  from diagrams-solve-0.1, F"
  (* (* x 27.0) y))