\left(\frac{1}{8} \cdot x - \frac{y \cdot z}{2}\right) + tt + \left(\frac{1}{8} \cdot x - \frac{y \cdot z}{2}\right)double f(double x, double y, double z, double t) {
double r21619062 = 1.0;
double r21619063 = 8.0;
double r21619064 = r21619062 / r21619063;
double r21619065 = x;
double r21619066 = r21619064 * r21619065;
double r21619067 = y;
double r21619068 = z;
double r21619069 = r21619067 * r21619068;
double r21619070 = 2.0;
double r21619071 = r21619069 / r21619070;
double r21619072 = r21619066 - r21619071;
double r21619073 = t;
double r21619074 = r21619072 + r21619073;
return r21619074;
}
double f(double x, double y, double z, double t) {
double r21619075 = t;
double r21619076 = 1.0;
double r21619077 = 8.0;
double r21619078 = r21619076 / r21619077;
double r21619079 = x;
double r21619080 = r21619078 * r21619079;
double r21619081 = y;
double r21619082 = z;
double r21619083 = r21619081 * r21619082;
double r21619084 = 2.0;
double r21619085 = r21619083 / r21619084;
double r21619086 = r21619080 - r21619085;
double r21619087 = r21619075 + r21619086;
return r21619087;
}




Bits error versus x




Bits error versus y




Bits error versus z




Bits error versus t
Results
| Original | 0.0 |
|---|---|
| Target | 0.0 |
| Herbie | 0.0 |
Initial program 0.0
Final simplification0.0
herbie shell --seed 2019179
(FPCore (x y z t)
:name "Diagrams.Solve.Polynomial:quartForm from diagrams-solve-0.1, B"
:herbie-target
(- (+ (/ x 8.0) t) (* (/ z 2.0) y))
(+ (- (* (/ 1.0 8.0) x) (/ (* y z) 2.0)) t))