Cannot sample enough valid points. (more)

\[1 \le y \le 9999\]
\[\begin{array}{l} \mathbf{if}\;\left(\left|y - \sqrt{y \cdot y + 1}\right| - \frac{1}{y + \sqrt{y \cdot y + 1}}\right) \cdot \left(\left|y - \sqrt{y \cdot y + 1}\right| - \frac{1}{y + \sqrt{y \cdot y + 1}}\right) = 0.0:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\frac{e^{\left(\left|y - \sqrt{y \cdot y + 1}\right| - \frac{1}{y + \sqrt{y \cdot y + 1}}\right) \cdot \left(\left|y - \sqrt{y \cdot y + 1}\right| - \frac{1}{y + \sqrt{y \cdot y + 1}}\right)} - 1}{\left(\left|y - \sqrt{y \cdot y + 1}\right| - \frac{1}{y + \sqrt{y \cdot y + 1}}\right) \cdot \left(\left|y - \sqrt{y \cdot y + 1}\right| - \frac{1}{y + \sqrt{y \cdot y + 1}}\right)}\\ \end{array}\]
\begin{array}{l}
\mathbf{if}\;\left(\left|y - \sqrt{y \cdot y + 1}\right| - \frac{1}{y + \sqrt{y \cdot y + 1}}\right) \cdot \left(\left|y - \sqrt{y \cdot y + 1}\right| - \frac{1}{y + \sqrt{y \cdot y + 1}}\right) = 0.0:\\
\;\;\;\;1\\

\mathbf{else}:\\
\;\;\;\;\frac{e^{\left(\left|y - \sqrt{y \cdot y + 1}\right| - \frac{1}{y + \sqrt{y \cdot y + 1}}\right) \cdot \left(\left|y - \sqrt{y \cdot y + 1}\right| - \frac{1}{y + \sqrt{y \cdot y + 1}}\right)} - 1}{\left(\left|y - \sqrt{y \cdot y + 1}\right| - \frac{1}{y + \sqrt{y \cdot y + 1}}\right) \cdot \left(\left|y - \sqrt{y \cdot y + 1}\right| - \frac{1}{y + \sqrt{y \cdot y + 1}}\right)}\\

\end{array}
double f(double y) {
        double r1803206 = y;
        double r1803207 = r1803206 * r1803206;
        double r1803208 = 1.0;
        double r1803209 = r1803207 + r1803208;
        double r1803210 = sqrt(r1803209);
        double r1803211 = r1803206 - r1803210;
        double r1803212 = fabs(r1803211);
        double r1803213 = r1803206 + r1803210;
        double r1803214 = r1803208 / r1803213;
        double r1803215 = r1803212 - r1803214;
        double r1803216 = r1803215 * r1803215;
        double r1803217 = 0.0;
        double r1803218 = r1803216 == r1803217;
        double r1803219 = exp(r1803216);
        double r1803220 = r1803219 - r1803208;
        double r1803221 = r1803220 / r1803216;
        double r1803222 = r1803218 ? r1803208 : r1803221;
        return r1803222;
}