Average Error: 0.0 → 0.0
Time: 3.7s
Precision: 64
\[x \cdot \left(1 - x \cdot 0.5\right)\]
↓
\[x \cdot \left(1 - x \cdot 0.5\right)\]
x \cdot \left(1 - x \cdot 0.5\right)
↓
x \cdot \left(1 - x \cdot 0.5\right)
double f(double x) {
        double r3588776 = x;
        double r3588777 = 1.0;
        double r3588778 = 0.5;
        double r3588779 = r3588776 * r3588778;
        double r3588780 = r3588777 - r3588779;
        double r3588781 = r3588776 * r3588780;
        return r3588781;
}
↓
double f(double x) {
        double r3588782 = x;
        double r3588783 = 1.0;
        double r3588784 = 0.5;
        double r3588785 = r3588782 * r3588784;
        double r3588786 = r3588783 - r3588785;
        double r3588787 = r3588782 * r3588786;
        return r3588787;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[x \cdot \left(1 - x \cdot 0.5\right)\]

  2. Final simplification0.0

    \[\leadsto x \cdot \left(1 - x \cdot 0.5\right)\]

Reproduce

herbie shell --seed 2019174 +o rules:numerics
(FPCore (x)
  :name "Numeric.SpecFunctions:log1p from math-functions-0.1.5.2, B"
  (* x (- 1.0 (* x 0.5))))