Average Error: 0.0 → 0.0
Time: 2.3s
Precision: 64
\[x \cdot \left(1 - x \cdot 0.5\right)\]
↓
\[\left(1 - x \cdot 0.5\right) \cdot x\]
x \cdot \left(1 - x \cdot 0.5\right)
↓
\left(1 - x \cdot 0.5\right) \cdot x
double f(double x) {
        double r77323 = x;
        double r77324 = 1.0;
        double r77325 = 0.5;
        double r77326 = r77323 * r77325;
        double r77327 = r77324 - r77326;
        double r77328 = r77323 * r77327;
        return r77328;
}
↓
double f(double x) {
        double r77329 = 1.0;
        double r77330 = x;
        double r77331 = 0.5;
        double r77332 = r77330 * r77331;
        double r77333 = r77329 - r77332;
        double r77334 = r77333 * r77330;
        return r77334;
}

Error

Bits error versus x

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Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[x \cdot \left(1 - x \cdot 0.5\right)\]

  2. Final simplification0.0

    \[\leadsto \left(1 - x \cdot 0.5\right) \cdot x\]

Reproduce

herbie shell --seed 2019174 +o rules:numerics
(FPCore (x)
  :name "Numeric.SpecFunctions:log1p from math-functions-0.1.5.2, B"
  (* x (- 1.0 (* x 0.5))))