0.5 \cdot \sqrt{2 \cdot \left(\sqrt{re \cdot re + im \cdot im} - re\right)}\sqrt{\left(\mathsf{hypot}\left(re, im\right) - re\right) \cdot 2} \cdot 0.5double f(double re, double im) {
double r821601 = 0.5;
double r821602 = 2.0;
double r821603 = re;
double r821604 = r821603 * r821603;
double r821605 = im;
double r821606 = r821605 * r821605;
double r821607 = r821604 + r821606;
double r821608 = sqrt(r821607);
double r821609 = r821608 - r821603;
double r821610 = r821602 * r821609;
double r821611 = sqrt(r821610);
double r821612 = r821601 * r821611;
return r821612;
}
double f(double re, double im) {
double r821613 = re;
double r821614 = im;
double r821615 = hypot(r821613, r821614);
double r821616 = r821615 - r821613;
double r821617 = 2.0;
double r821618 = r821616 * r821617;
double r821619 = sqrt(r821618);
double r821620 = 0.5;
double r821621 = r821619 * r821620;
return r821621;
}



Bits error versus re



Bits error versus im
Results
Initial program 38.2
Simplified13.4
Final simplification13.4
herbie shell --seed 2019174 +o rules:numerics
(FPCore (re im)
:name "math.sqrt on complex, imaginary part, im greater than 0 branch"
(* 0.5 (sqrt (* 2.0 (- (sqrt (+ (* re re) (* im im))) re)))))