Average Error: 5.7 → 0
Time: 3.8s
Precision: 64
\[e^{\log a + \log b}\]
↓
\[b \cdot a\]
e^{\log a + \log b}
↓
b \cdot a
double f(double a, double b) {
        double r9841829 = a;
        double r9841830 = log(r9841829);
        double r9841831 = b;
        double r9841832 = log(r9841831);
        double r9841833 = r9841830 + r9841832;
        double r9841834 = exp(r9841833);
        return r9841834;
}
↓
double f(double a, double b) {
        double r9841835 = b;
        double r9841836 = a;
        double r9841837 = r9841835 * r9841836;
        return r9841837;
}

Error

Bits error versus a

Bits error versus b

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original5.7
Target0
Herbie0
\[a \cdot b\]

Derivation

  1. Initial program 5.7

    \[e^{\log a + \log b}\]

  2. Simplified0

    \[\leadsto \color{blue}{b \cdot a}\]

  3. Final simplification0

    \[\leadsto b \cdot a\]

Reproduce

herbie shell --seed 2019173 +o rules:numerics
(FPCore (a b)
  :name "Exp of sum of logs"

  :herbie-target
  (* a b)

  (exp (+ (log a) (log b))))