Average Error: 0.0 → 0.0
Time: 19.8s
Precision: 64
\[0.0 \le x \le 2\]
\[x + x \cdot x\]
\[x + x \cdot x\]
x + x \cdot x
x + x \cdot x
double f(double x) {
        double r11783206 = x;
        double r11783207 = r11783206 * r11783206;
        double r11783208 = r11783206 + r11783207;
        return r11783208;
}

double f(double x) {
        double r11783209 = x;
        double r11783210 = r11783209 * r11783209;
        double r11783211 = r11783209 + r11783210;
        return r11783211;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.0
Target0.0
Herbie0.0
\[\left(1 + x\right) \cdot x\]

Derivation

  1. Initial program 0.0

    \[x + x \cdot x\]
  2. Final simplification0.0

    \[\leadsto x + x \cdot x\]

Reproduce

herbie shell --seed 2019173 
(FPCore (x)
  :name "Expression 2, p15"
  :pre (<= 0.0 x 2.0)

  :herbie-target
  (* (+ 1.0 x) x)

  (+ x (* x x)))