Average Error: 3.2 → 3.2
Time: 14.3s
Precision: 64
\[x \cdot \left(1 - y \cdot z\right)\]
↓
\[\left(1 - y \cdot z\right) \cdot x\]
x \cdot \left(1 - y \cdot z\right)
↓
\left(1 - y \cdot z\right) \cdot x
double f(double x, double y, double z) {
        double r49772215 = x;
        double r49772216 = 1.0;
        double r49772217 = y;
        double r49772218 = z;
        double r49772219 = r49772217 * r49772218;
        double r49772220 = r49772216 - r49772219;
        double r49772221 = r49772215 * r49772220;
        return r49772221;
}
↓
double f(double x, double y, double z) {
        double r49772222 = 1.0;
        double r49772223 = y;
        double r49772224 = z;
        double r49772225 = r49772223 * r49772224;
        double r49772226 = r49772222 - r49772225;
        double r49772227 = x;
        double r49772228 = r49772226 * r49772227;
        return r49772228;
}

Error

Bits error versus x

Bits error versus y

Bits error versus z

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 3.2

    \[x \cdot \left(1 - y \cdot z\right)\]
  2. Using strategy rm

  3. Applied *-commutative3.2

    \[\leadsto \color{blue}{\left(1 - y \cdot z\right) \cdot x}\]

  4. Final simplification3.2

    \[\leadsto \left(1 - y \cdot z\right) \cdot x\]

Reproduce

herbie shell --seed 2019173 
(FPCore (x y z)
  :name "Data.Colour.RGBSpace.HSV:hsv from colour-2.3.3, I"
  (* x (- 1.0 (* y z))))